What is the solution set of 4x = y and 2x2 − y = 0?

(2,8)

Step-by-step explanation:

4x = y equ1

2x^2 - y =0 equ2

y = 4x

substitute the value of y into equ 2

Then we have; 2x^2 - 4x = 0

2x (x - 2) = 0

2x = 0

x = 0/2 = 0

x - 2 = 0

x = 2.

then put the values of x in equ 1...

y = 4x

y = 4(0)

y = 0

y = 4x

y = 4(2)

y = 8

i.e (2,8)

I hope this helps.

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.

answer: the correct answer is -32

step-by-step explanation: