If a gas is 0.8L at 900 mm Hg and 400K, what is the new pressure if the volume decreases to 0.5L and 300K?

The new pressure of the gas is 1080 mmHg

Explanation:

The general equation provides a way to calculate the relationship between changesnp in volume, temperature and pressure of a given mass of gas.

The general gas equation is given as P1V1/T1 = P2V2/T2

Where P1 is initial pressure of gas

V1 is initial volume of gas

T1 is initial temperature of gas

P2 is final pressure of gas

V2 is final volume of gas

T2 is final temperature of gas

From the given question, P1 = 900 mmHg, V1 = 0.8 L, T1 = 400 K, P2 = ?, V2 = 0.5 L, T2 = 300 K

Making P2 subject of the general gas equations:

P2 = P1V1T2/V2T1

P2 = (900 × 0.8 × 300) / (0.5 × 400)

P2 = 1080 mmHg

Therefore, the new pressure of the gas is 1080 mmHg.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

i have no clue hope you find the answer