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Mathematics, 19.06.2020 05:57 tzartiger12

∠BCA ≅ ∠DAC and ∠BAC ≅ ∠DCA by


∠BCA ≅ ∠DAC and ∠BAC ≅ ∠DCA by

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∠BCA ≅ ∠DAC and ∠BAC ≅ ∠DCA by
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