Use the given measurements on the triangle to write the following trig ratios and answer the question that follows Please help!

1. sin P = 20/29

cos P = 21/29

tan P = 20/21

sin Q = 21/29

cos Q = 20/29

tan Q = 21/20

2. We can notice that the sin and cos of P vs Q are switched and the tan's are a reciprocal of each other

Step-by-step explanation:

For Part 1

With knowledge of SOH CAH TOA

Sin = Opp/Hyp

Cos = Adj/Hyp

Tan = Opp/Adj

So:

sin P = 20/29

cos P = 21/29

tan P = 20/21

sin Q = 21/29

cos Q = 20/29

tan Q = 21/20

For Part 2

We can notice that the sin and cos of P vs Q are switched and the tan's are a reciprocal of each other

false

step-by-step explanation:

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130