Atall tube is evacuated, and its stopcock closed. the open end of the tube is immersed into a container of water (density 103 kg/m3) that is open to the atmosphere (pressure 105 n/m2). when the stopcock is opened, how far up the tube will the water rise?

The water will rise to a height, H = 10.20 m

Given:

Atmospheric Pressure, P =

density of water,

Solution:

The water in the tube will rise to the point where the weight is balanced by the force as a result of the atmospheric pressure.

Therefore,

Pressure, P =

where

g = acceleration due to gravity = 9.8 m/s

H = height of water in the tube

Now,

Putting the values in the above formula:

H = 10.20 m

The water will rise to a height of 10 meters.

Explanation:

The pressure exerted at a height h is given by :

g is acceleration due to gravity.

h = 10 meters.

The water will rise to a height of 10 meters.

Learn more about the atmospheric pressure, refer:

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow