Which is the best first step when solving the following system of equations? x + y = 3. 4 x minus y = 7. Multiply the first equation by 4. Add the first equation to the second equation. Multiply the second equation by Negative 1. Subtract the second equation from the first equation.

just add the equation and solve it then the value of X could be found then put the value of X and the value of y can be found. Just like in the below

Step-by-step explanation:

X+y=3 equation 1

4x-y=7 equation 2

adding equation 1 and 2

X+y=3

+ 4x-y=7

5x = 10

X = 10/5

X = 2

putting the value of X in equation 1

or, 2+y=3

or, y = 3-2

Thus, y = 1

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

marco saved more.   he saved $35 more.

step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35