The probability that Rahul succeeds at any given free-throw is 70%. He was curious how many free-throws

he can expect to succeed in a sample of 15 free-throws.

He simulated 30 samples of 15 free-throws where each free-throw had a 0.7 probability of being

successful

Rahul counted how many free-throws were successful in each simulated sample. Here are his results:

10 11 12 13 14 15

# of free-throw successes

Use his results to estimate the probability that he succeeds at 11 or fewer free-throws in a sample of 15

free-throws.

Give your answer as either a fraction or a decimal.

P(11 or fewer successes)

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!