Which ordered pairs are in the solution set of the system of linear inequalities? y > Negative one-halfx y < One-halfx + 1

Option C.

Step-by-step explanation:

The given system of linear inequalities is

The related equations are

The above equations are 2 straight lines. The first dashed line has a negative slope and goes through (0, 0) and (4, negative 2). Everything above the line is shaded.

The second dashed line has a positive slope and goes through (negative 2, 0) and (2, 2). Everything below the line is shaded.

The shaded region represents the solution of given system of linear inequalities.

All the ordered pairs lies in the shaded region are the solution.

Consider the missing options are:

All ordered pairs  lie in the shaded region.

Therefore, the correct options is C.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

mathpapa

step-by-step explanation: