Distributed with a mean frequency of 200 MHz and a variance of 9 MHz. The governmentaccepts product that falls between 195.500 MHz and 204.935 MHz. What percent of ourproduct will be acceptable to the government? Note that ifZis a standard normal randomvariable

88.32% of the product will be acceptable to the government.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 200 MHz

Variance = 9 MHz

We are given that the distribution of  frequency is a bell shaped distribution that is a normal distribution.

Formula:

P(frequency falls between 195.500 MHz and 204.935 MHz)

Thus, 88.32% of the product will be acceptable to the government.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116