A northbound train left at midnight. three hours later, a southbound train left the same station. at 6 am the two trains were 330 miles apart. find the rate of each train if the northbound train traveled 10 miles per hour faster than the southbound train

Step-by-step explanation:

In this question u can use relative speed of opposite direction

suppose speed of southbound train is x miles per hour so northbound train has speed of x+10 miles per hour.

Speed of tain1+ speed of train 2= Total distance/ total time

(x+10+x)=330/6

2x+10= 330/6

2x= 45

x=22.5 miles per hour (southbound train)

northbound train 22.5+10=32.5 miles per hour

practice. practice. practice.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right