Ucsd reddit A watermelon is thrown down from the 7th floor of Urey Hall at UCSD. If the initial height of the watermelon is 21.0 meters, and it is thrown straight downward with an initial downward velocity of 3.00 m/s. How far will the watermelon have fallen from its starting height after 1.50 seconds?

15.525 feet

Step-by-step explanation:

GIVEN: A watermelon is thrown down from the floor of Urey Hall at UCSD. If the initial height of the watermelon is , and it is thrown straight downward with an initial downward velocity of .

TO FIND: How far will the watermelon have fallen from its starting height after seconds.

SOLUTION:

initial height of watermelon

initial velocity of watermelon

acceleration due to gravity

According to newton's law of motion

when seconds

Hence watermelon will have fallen 15.525 feet from its starting height after 1.5 seconds

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure