Aschool choir has 80 students; 36 of them are in seventh grade. also, 40 students in the choir are girls; 18 of them are in seventh grade. what is the probability that a student picked at random from the choir is either a girl or is in seventh grade? a. `27/40` b. `29/40` c. `13/40` d. `33/40`

B.  `29/40`

Step-by-step explanation:

These events are not mutually exclusive.  This means they can happen at the same time.

For two events A and B that are not mutually exclusive,

P(A or B) = P(A)+P(B) - P(A and B)

Our events are:

P(girl or 7th grade) = P(girl)+P(7th grade)-P(girl and 7th grade)

There are 40 girls out of 80 students:

P(girl or 7th grade) = 40/80+P(7th grade)-P(girl and 7th grade)

There are 36 7th graders in the choir out of 80 students:

P(girl or 7th grade) = 40/80+36/80-P(girl and 7th grade)

There are 18 7th grade girls in the choir:

P(girl or 7th grade) = 40/80+36/80-18/80 = 76/80-18/80 = 58/80

Both the numerator and denominator are divisible by 2:

(58÷2)/(80÷2) = 29/40

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

7,24

step-by-step explanation: