A company has 4 employees named Joe, Steve, Mary, and Alice (abbreviate the names J, S,M and A). The company randomly selects two employees to be part of a committee. Joe and Steve are males, while Mary and Alice are females. The sample space for this is:
S = {(J, S),(J, M),(J, A),(S, M),(S, A),(M, A)}.
Denote the following events:
A = the event/set of picking exactly one female.
B = the event/set of picking at least 1 female.
a. Write out the event/set A
b. Write out the event/set B.
c. List the outcomes/elements in the event A^c
d. List the outcomes/elements in the event A ∩ B.

answer: b

step-by-step explanation: im sorry bro bro but thats not a eqation the human mind can answer and plus im a devil

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

i’ll just s take the points thxs