![A = 2\int\limits^1_7 {r} \, dr \int\limits^\pi _0 {[14 cos(theta) - 7]} \, d(theta) \\\\A = 2\int\limits^1_7 {r} \, dr [14 sin (theta) - 7(theta)]^\pi ^/^3_0 \\\\A = 2[14 sin(\pi /3) - 7(\pi /3)][\frac{r^2}{2}]^1^5_7_._5\\ \\A = 4.794 X 89.375\\\\A = 404. 49](/tpl/images/0589/1935/a4503.png)
Find the area of the region that lies inside the first curve and outside the second curve.
r =...
Mathematics, 08.04.2020 08:53 Krazyyykiddd
Find the area of the region that lies inside the first curve and outside the second curve.
r = 15 cos θ, r = 7 + cos θ
Answers: 2
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