How many real solutions does 2x^2-4x+3=5

Step-by-step explanation:

To find how many real solutions it has you have to find the solutions.

The quadratic formula is x=  

(the A with a weird line over it shouldn't be there but i cant get rid of it)

for the equation you gave me, you subtract 5 from both sides so it is equal to 0.  It should be:

This equation is now in the format:

Now plug in what you have for a, b, and c  (a= 2, b= -4, c= -2)

This will give you:

(again ignore that letter)

Now simplify it to:

There are 2 real solutions because 1 plus the square root of 2 and 1 minus the square root of two are both real. (If it was 1 plus or minus the square root of a negative number it would be 0 real solutions because you cant take the square root of a negative number)

Sorry if this is confusing