Solve x^2 + 5x + 6 = 0

X=-2, X=-3

Step-by-step explanation:

The original formula would be x^2+bx+c. I factored out the problem and made a t chart that multiplies to 6 (a*c) and adds to 5 (b). 3 and 2 are the only ones that add to 5 and multiply to 6. I then grouped x^2+3x+2x+c because the c doesn’t change And 3x+2x are the multiples. Then i took out common terms and got (x+2)(x+3)=0 because we solve for x. Then when you move them you get -2 and -3 equal x. Hope it helps you.

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step-by-step explanation:

geometry: triangles

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answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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