What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?
y=-1x +33
y=-3x + 36
y = 4x - 16
y = 4x + 16

y = 4x + 16

Step-by-step explanation:

y - 1 = 4(x + 3)

Has a slope of 4

y = 4x + c

32 = 4(4) + c

32 - 16 = c

c = 16

y = 4x + 16

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3