Asample of nitrogen occupies a volume of 500ml at 60 and 500 mm hg of pressure. what will its volume be at stp\

Answer : The volume at STP will be 0.2944 L

Solution : Given,

Initial volume = 500 ml

Initial temperature =    

Initial pressure = 500 mmHg =  

At STP,

Temperature = 298 K

Pressure = 1 atm

Formula used :

where,

= initial pressure

= pressure at STP

= initial temperature

= temperature at STP

= initial volume

= volume at STP

Now put all the given values in this formula, we get

By rearranging the terms, we get the volume at STP

       (1 L = 1000 ml)

Therefore, the volume at STP will be 0.2944 L

b) mutualism

hope this : )

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml