Can someone please help me!!

  rotation 90° CW about the origin we defined

Step-by-step explanation:

The image has the same orientation (clockwise order of vertices) as the pre-image, so an even number of reflections is involved. These cannot be reflections across the x- or y-axes. The longest edge has an east-west orientation in the pre-image and a south-north orientation in the image. Any reflections must have a net effect of a rotation 90° CW.

Equivalently, the image is rotated 90° clockwise from the pre-image.

With a suitable choice of center of rotation, the image can be obtained with a single 90° CW rotation transformation.

If we define the lower left corner of the pre-image as having coordinates (-1, 2), then a 90° CW rotation about (0, 0) will yield the image.

the forst and 3rd

step-by-step explanation:

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.