A store sells bread and milk. On Tuesday, 3 loaves of bread and 2 litres of milk were sold for €6.25. On Thursday
4 loaves of bread and 5 litres of milk were sold for €10.90. If b = the price of a loaf of bread and m = the price of
one litre of milk, Tuesday's sales can be written as 3b+2m=6.25.

Part A Using simplest terms, write an equation in band m for Thursday's sales.

PartB calculate the values of b and m

A store sells bread and milk. On Tuesday, 3 loaves of bread and 2 litres of milk were sold for €6.25. On Thursday  4 loaves of bread and 5 litres of milk were sold for €10.90. If b = the price of a loaf of bread and m = the price of

one litre of milk, Tuesday's sales can be written as 3b+2m=6.25.

Part A Using simplest terms, write an equation in band m for Thursday's sales.  

PartB calculate the values of b and m

3b + 2m= 6.25  >> Tuesday equation 1

4b +  5m = 10.90 >> Thursday equation 2

Subtract equation 1 and 2

3b+2m-6.25-4b+5m-10.90= 0

b+7m-4.65= 0

b+7m= 4.65+0

b+7m= 4.65

b= 4.65 - 7m

if b= 4.65-7m

then substitute b in b+7m=4.65

4.65-7m+7m= 4.65

4.65-m= 4.65

4.65-4.65= m

m= 0

Step-by-step explanation:

a) 4b + 5m = 10.90

b) m = 1.1, b = 1.35

Step-by-step explanation:

a) 4b + 5m = 10.90

b)

4b + 5m = 10.90

3b + 2m = 6.25

b = (10.90 - 5m)/4

b = 2.725 - 1.25m

3b + 2m = 6.25

3(2.725 - 1.25m) + 2m = 6.25

8.175 - 3.75m + 2m = 6.25

1.75m = 1.925

m = 1.1

b = (10.9 - 5.5)/4

b = 1.35

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.