Which of the following are possible equations of a parabola that has no real solutions and opens downward?
y>= -(x+4)^2 - 2
y>= -(x+4)^2 + 2
y>= -x2-2
y>=(x-4)^2 + 2
y>= -(x-4)^2 - 2

Step-by-step explanation:

The vertex form of a parabola is given as

If this parabola opens downward, then a<0.

This means for a function opening downward not to have a solution, the k value must also be negative and taking a square root of a negative number will not give real solution.

From the given options, examples of such functions are:

and

d 192

step-by-step explanation:

we find our area to find area we multiply thoses numbers to get our answer so our area is 192