Kelly and Fawn both went to food land to buy eggs and bread. Kelly bought 3 dozen eggs and 5 loads of bread for $33. Fawn bought two dozen eggs and 2 loads of bread for $18. How much is each idem?

The answer to your question is below

Step-by-step explanation:

Data

Kelly bought    3 dozens of eggs and 5 loads of bread   cost = $33

Fawn bought   2 dozens of eggs and 2 loads of bread   cost = $18

Cost of each item = ?

Process

1.- Write one equation for Kelly and another for Fawn to solve this problem.

eggs = e

bread = b

                  3e + 5b = 33            Equation l

                  2e  + 2b = 18            Equation ll

2.- Solve by elimination

- Multiply equation l by 2 and equation ll by -3

                     6e + 10b = 66

                    -6e  - 6b  =-54

  Simplify        0  + 4b = 12

-Solve for b              b = 12/4

                                 b = 3

3.- Substitute b in equation ll to find e            

                   2e + 2(3) = 18

                   2e + 6 = 18

                   2e = 18 - 6

                   2e = 12

                     e = 12/2

                     e = 6

4.- Conclusion

A dozen of eggs costs $6

A load of bread cost $3

Eggs are 6 dollars a dozen and bread is 3 dollars a loaf.

Step-by-step explanation:

Let the price of a dozen eggs be e dollars and the price of the bread be b dollars.

So we have the system:

3e + 5b = 33

2e + 2b = 18

We use the method of elimination:

Multiply the first equation by 2 and the second by -5:

6e + 10b =  66

--10e - 10b = -90      Adding:-

-4e = -24

e = 6.

Substitute e = 6  in the first equation:

18 + 5b = 33

5b = 33 - 18

5b = 15

b = 3.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt