The length of a new rectangular playing field is 8 yards longer than triple the width. If the perimeter of the rectangular playing field is 352 yards, what are its dimensions?

Step-by-step explanation:

let the width be x

then length is 3x+8

now

we have

p= 2(l+b)

or, 352=2(3x+8+x)

or, 352/2=4x+8

or, 176=4x+8

or, 176-8=4x

or, 168=4x

or, x=168/4

therefore x=42

width =42 yards

length =3x+8=3*42+8=134yards

HOPE IT HELPS

a² + b²= c²

24² + 7² = c²

c= 25