Mathematics, 26.03.2020 16:55 mullanebrianot3dpw
6tβ20β32u6t -20-32u6tβ20β32u6, t, minus, 20, minus, 32, u when t=6t=6t=6t, equals, 6 and u=14u=\dfrac14u=41u, equals, start fraction, 1, divided by, 4, end fraction.
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6tβ20β32u6t -20-32u6tβ20β32u6, t, minus, 20, minus, 32, u when t=6t=6t=6t, equals, 6 and u=14u=\dfra...
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