If an arch is in the shape of a parabola and it spans 80 ft with a maximum height of 20 feet what is the equation for the parabola and what is it's height from the center?

Step-by-step explanation:

Given that:

As we know that the Parabola is of type :

= -4a(y - ) where: is the origin of the line so we have:

and

<=> = -4a(y-20)

at y = 0, we have:

= -4a(0-20)

<=>

<=> x = ±

But we know that 2x= 80 <=> x= 40, so:

40 =

<=> 1600 = 80a

<=> a = 20

The equation for the parabola is:

It's height from the center at x= 0 => y= 20

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: yard ramps with a level off platform are typically 36 feet long. truck, rather than at an angle, enabling access to those pallets at the very back of the truck. if you are using your yard ramp to convert a loading dock into a drive-in door, we even at 60 inches (5 feet) high and a 30 foot ramp, the slope of the ramp will be less

step-by-step explanation: