Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find the probability that x lies between 6 and 13. (c) Find the probability that x lies between 9 and 20. (d) Find the probability that x lies between 11 and 18.

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13.

So

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So

28% probability that x lies between 11 and 18.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.