Mathematics, 11.03.2020 20:52 tvrgrvJfbhh3881

The exam scores (out of 100 points) for all students taking an introductory Statistics course are used to construct the following boxplot. Based on this boxplot, the interquartile range is closest to 50. 25. 80. 10.

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Answer from: harmonytaylor13

The inter quartile range is 55

Step-by-step explanation:

Interquartile range:-

Definition:-

The inter quartile range is the difference between the upper (Q3) and lower(Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest.

Interquartile range = higher quartile - lower quartile

given data 50.25.80.10

write the ascending order 10 25 50 80

Step:-1

Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is odd, then the median is

$({\frac{n+1}{2} })^{th}$ observations

Step2:-

The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is even, then the median is $({\frac{n}{2} })^{th}$

$({\frac{n+1}{2} })^{th}$

In given data the number of observations is '4'(even)

If the number of observations is even, then the median is $({\frac{n}{2} })^{th}$

$({\frac{n+1}{2} })^{th}$

median is $({\frac{4}{2} })^{th}$ is 2 observations and $({\frac{4+1}{2} })^{th}$ is 2.5 observations.

so we have to select average of these two observations.

therefore the median is '3' observation

median of the given data = 50

Step:3

Interquartile range = higher quartile - lower quartile

= 80-25

=55

Answer from: Quest

Answer

1 number

explanation

if we use a graphing calculator, there is only one such number $c\in[0.5,0.75]$ that satisfies the conclusion of the mean value theorem, that is, a number $c\in[0.5,0.75]$ such that

$f'(c) = \dfrac{f(0.75) - f(0.5)}{0.75-0.5},$

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

Answer from: Quest

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

$y=-\dfrac{1}{2}x+8$

is for x = 0. substitute:

$y=-\dfrac{1}{2}(0)+8=0+8=8$

y-intercept is 8 → point (0, 8).

10 points and brainliest its for my semester test

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