A particle (mass = 2.0 mg, charge = −6.0 μC) moves in the positive direction along the x axis with a velocity of 3.0 km/s. It enters a magnetic field of ( ) mT. What is the acceleration of the particle?

Complete Question

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The acceleration would be      

Explanation:

The objective of this solution is to obtain the acceleration of the particle

       Now looking at Newton law which is mathematically represented as

  Where F is the force experience by a particle

              m is the mass of the particle

              a is the acceleration of the particle

  And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as

Where q is the charge of the particle

             v is the velocity of the  charge

             B is the magnetic field the charge is under it influence

  Now equating this two formulas

 Making a the subject we have

In the question the direction of the is in the positive x-axis which is hence the direction would be in the direction

      So substituting   for B

      Substituting        for v  and for q

According to vector multiplication

     So

i believe the answer would be:

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i think the answer would be reserve.