Suppose that a consumer has $10 to spend. A candy bar costs $2 and a bag of peanuts costs $1.50. Which combination of candy bars and peanuts would NOT be attainable for this consumer?

The combination of two candy bars and five bags of peanuts would NOT be possible for this consumer

Step-by-step explanation:

First, the equation that represents what is stated by this statement is determined. Being "c" the number of candy bars and "p" the amount of peanut bag that the consumer buys, then the amount of money that the consumer spends on each of these items, knowing their unit prices, is:

A consumer has $ 10 to spend, so what they spend on candy bars and peanut bags should add up to $ 10. This is expressed as:

amount of candy bars*$2+amount of peanut*$1.50=$10

Then the options proposed must comply with said expression. Although it may also happen that the amount of candy bar and peanut bags purchased by the consumer do not reach $ 10. But this value must always be less than $ 10, because the consumer cannot spend more money than he has, but he can spend less. So:

1*$2+4*$1.50=$8

2*$2+5*$1.50=$11.5

2*$2+1*$1.50=$5.5

3*$2+1*$1.50=$7.5

You can see that the combination of two candy bars and five bags of peanuts would NOT be possible for this consumer because the expense is greater than the money they have available.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%