Assume a population of 46, 51, 53, and 59. Assume that samples of size nequals=2 are randomly selected with replacement from the population. Listed below are the sixteen different samples. Complete parts (a) through (c). 46,46 46,51 46,53 46,59 51,46 51,51 51,53 51,59 53,46 53,51 53,53 53,59 59,46 59,51 59,53 59,59 a. Find the median of each of the sixteensamples, then summarize the sampling distribution of the medians in the format of a table representing the probability distribution of the distinct median values. Use ascending order of the sample medians.

Step-by-step explanation:

There are four values 46, 51, 53, 59

we have to draw 2 sampler with replacement

sampler     median     samler     median

46.46              46          53.46         49.5

46.51               48.5        53.51          52

45..53              49.5        53.53         53

46.59               52.5        53.59         56

51.46                 48.5        59.46        52.5

51.51                   51           59.51           55

51.53                   52          59.53          56

51.59                   55          59.59          59

sampling distribution of the median

median                   probability

46                               1/16

48.5                             2/16      

49.5                             2/16  

52.5                             2/16    

51                                  1/16

52                                2/16

55                                 2/16

53                                  1/16

56                                  2/16

59                                   1/16    

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy