Toretto and O’Conner graphed two different quadratic functions in vertex form. Toretto graphed f(x)=(x+3)^2+1 and O’Conner graphed g(x) =-(x-3)^2+1 . Both of them drew the same graph.

Yo sup??

By observing the graph we can say that minimum value of Toretto graph occurs at x=-3

whereas the minimum value of OConner graph occurs at x=3 .

In the given figure the minimum value is at x=3

therefore OConner is correct because the vertex is (3,1)

Hope this helps

f(x) = y

f(-3) = -5

step-by-step explanation: