How do i solve a quadratic equation like this

Solve.
3n2 = 147

A{–3, 7}

B{–7, 3}

C{–49, 49}

D{–7, 7}

Option D. {–7, 7}

Step-by-step explanation:

3n^2 = 147

First, divide both side 3

n^2 = 147/3

n^2 = 49

Next, rearrange the variables to one side of the equation as shown below:

n^2 — 49 = 0

n^2 — 7^2 = 0

The above is now difference of two squares. This can be solve by doing the following:

(n — 7)(n + 7) = 0

n — 7 = 0 or n + 7 = 0

n = 7 or n = —7

D{–7, 7}

Dtep-by-step explanation:

3n² = 147

n² = 147/3

n² = 49

n = 7, -7

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1