A man paid $101 for 2 pairs of trousers and 3 shirts . He found that 7 pairs of trousers and 3 shirts would cost $331. Find the cost of a pair of trousers and a shirt

The cost of a pair of trousers and a shirt is $46 and $3 respectively.

Step-by-step explanation:

Let us assume the pairs of trousers be X

And, the pairs of trousers be Y

So, the first equation is

2X + 3Y = $101

And, the second equation is

7X + 3Y = $331

Now substituting this two equations

2X + 3Y = $101

7X + 3Y = $331

-5X = -$230

X = $46

Now put the X values in one of the equation to find out the Y value

So,

2 × $46  + 3Y = $101

$92 + 3Y = $101

Y = $3

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

step-by-step explanation:

the true ones are a b and d