A CMOS module of a computer system contains three electrical components, A, B, and C. All three components must function for the CMOS module of the computer system to work properly. The probability that component A fails is 0.0015, the probability that component B fails is 0.0005, while the probability that component C fails is 0.0001. Assuming the three components function independently, what is the probability that the CMOS module of the computer system functions?

The probability that the CMOS module of the computer system functions = 0.9979

Step-by-step explanation:

The CMOS module functions when all 3 components work.

Probability that component A works = 1 - (Probability that component A fails) = 1 - 0.0015 = 0.9985

Probability that component B works = 1 - (Probability that component B fails) = 1 - 0.0005 = 0.9995

Probability that component C works = 1 - (Probability that component Cfails) = 1 - 0.0001 = 0.9999

Probability that the CMOS module functions = probability that all three components work = 0.9985 × 0.9995 × 0.9999 = 0.9979

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

could you provide figure.