Identify the 42nd term of an arithmetic sequence where a1 = -12 and a27 = 66

The arithmetic formula is expressed as an = a1 + d *(n-1)where n is an integer. Substituting from the given a1 = -12 and a27 = 66, 66 = -12 + d *(27-1). hence  , d is equal to 3. a42 thus using the formula is equal to 111. The final answer to this problem is 111.

Ibelieve the answer is pollen contains the sperm cell because the flower only has female parts and the pollen is the male part of the flower i believe