Please help me due tomorrow

What is the equation of the lines that passes though the points (-1,3) and (-2, -3)?

Show ur work or evidence

A. Y=6x-9

B. Y=6x+9

C. Y=-6x-9

D. Y=-6x+9

B. y=6x+9

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-3-3)/(-2+1)= (-6)/(-1)= 6

m=6

y=mx+b       y=6x+b

plug in one of the points for b

-3=6(-2)+b    -3=-12+b  -3+12= 9

y=6x+9

First you have to find the slope of the line

m = y2-y1/x2-x1

m = -3 - 3/-2 - -1

m  = -6/-1

m = 6

then using the y = mx +b

3 = 6(-1) + b

3 = -6 + b

9 = b

y = 6x + 9      B is the answer

sine

step-by-step explanation:

i think it might be a but you might want a second opinion