A swimming pool has average dimensions of 40. feet by 20. feet by 6.0 feet. Given the density of water is 1.0 g/mL, how many kilograms of water are needed to fill the pool?

135921 kilograms of water are needed to fill the pool.

Step-by-step explanation:

The formula for determining the volume of the rectangular pool is expressed as

Volume = length × width × height

The swimming pool has average dimensions of 40. feet by 20. feet by 6.0 feet. This means that the volume of the pool is

Volume = 40 × 20 × 6 = 4800 cubic feet.

1 cubic feet = 28316.847 millilitres

4800 cubic feet = 4800 × 28316.847

= 135920865.6 millilitres

Given the density of water is 1.0 g/mL, the weight of 135920865.6 millilitres of water would be

1 × 135920865.6 = 135920865.6 g

1000g = 1 kilogram

135920865.6g = 135920865.6/1000

= 135921 kg

$9.41

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