The length of a standard jewel case is 4 centimeters more than its width. The area of the rectangular top of the case is 221 cm^2 What is the length and width of the jewel case?

Simply 8x squared + 5(7x squared- x) - 2x =

Given δjkl : δxyz, find x. a)10 b)12 c)16 d)20

Thirteen bowlers were asked what their score was on their last game. the scores are shown below 190,150,154,194,181,190,170,151,170,178,161,180 find the range of the bowlers score a.56 b.44 c.34 d.23