A rectangular photograph that is 5 inches wide and 7 inches long is enlarged to produce a photgraph that is 12 inches wide, if the enlarged photograph is in proportion to the original, what is the length in inches of the large photograph?

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  16.8 inches

Step-by-step explanation:

The length is 7/5 = 1.4 times the width. The length of the enlargement will be ...

  (12 in)×1.4 = 16.8 in

The large photo will be 16.8 inches long.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2