A fair die is rolled 10 times. What is the probability that an odd number (1, 3, or 5) will occur fewer than 3 times?

The probability that an odd number rolls of a die for less than 3 times is 0.054.

Step-by-step explanation:

The sample space of rolling a fair die is, S = {1, 2, 3, 4, 5, 6}

The odd numbers are, {1, 3, and 5}.

The probability that an odd number occurs is:

The die was rolled n = 10 times.

Let X = number of rolls in which an odd number occurs.

The random variable

The probability distribution of binomial is:

Compute the probability that an odd number will occur less than 3 times as follows:

Thus, the probability that an odd number rolls of a die for less than 3 times is 0.054.

i need the options

step-by-step explanation:

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42