If f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (fºg)(x)? (3x + 2)(x2 + 1) 3x2 + 1 + 2 (3x + 2)2 + 1 3(x2 + 1) + 2

3(x2 + 1) + 2

A. (3x + 2)(x2 + 1) WRONG bc = 3x^3

B. 3x2 + 1 + 2 Wrong bc 3x^+3

C. (3x + 2)2 + 1 wrong bc 6x+5

D. 3(x2 + 1) + 2Correct

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

∞ this is your sign