Ineed with this geometry question.

Given that AC ≅ BC, the sides are of equal measures.

CD is a side in both ΔACD and ΔBCD, so the side is equal in both triangles.

Given that CD if the bisector of ∠ACB, the two angles produced are equal: ∠ACD ≅ ∠BCD.

∠ACB is contained between AC and CD in ΔACD. ∠ACB is contained between BC and CD in ΔBCD.

Therefore by the SAS postulate, ΔACD ≅ ΔBCD.

Step-by-step explanation:

The SAS postulate says that if two triangles have a contained angle between two sides that are known to be equal in the other triangle, then the triangles are congruent.

Prove that two sides are equal, then prove that an angle that is between those two sides is also equal.

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step-by-step explanation: