Y=1/3x-4; y=7/3x+4 solve by substitution

Answer Problem 1: 3*(y+4)

Show Work:

1) y = (1/3)*x-4 // - (1/3)*x-4

2)  y-((1/3)*x)+4 = 0

3) (-1/3)*x+y+4 = 0

4)  y-1/3*x+4 = 0 // - y+4

5)  -1/3*x = -(y+4) // : -1/3

6)  x = (-(y+4))/(-1/3)

7)  x = 3*(y+4)

8) x = 3*(y+4)

Answer Problem 2: Y=-7/12

Show Work:

Step 1: Flip the equation.

7/3 x+4=y

Step 2: Add -4 to both sides.

7/3x+4+−4=y+−4

7/3x=y−4

Step 3: Divide both sides by 7/3.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.