When a plane flies into the wind, it can travel 3000 ml in 6 h . when it flies with the wind, it can travel the same distance in 5 h. find the rate of the plane in still air and the rate of the wind

Step-by-step explanation:

If p and w represent the speeds of the plane and wind, respectively, the speed into the wind is ...

  p - w = (3000 mi)/(6 h) = 500 mi/h

And, the speed with the wind is ...

  p + w = (3000 mi)/(5 h) = 600 mi/h

Adding these two equations gives us ...

  2p = 1100 mi/h

  p = 550 mi/h . . . . . . . divide by 2

Then the wind speed is ...

  w = 600 mi/h - p = (600 -550) mi/h

  w = 50 mi/h

The rate of the plane in still air is 550 mi/h; the rate of the wind is 50 mi/h.

Step-by-step explanation:

let speed of plane in still air =x

speed of wind=y

(x-y)6=3000

x-y=3000/6=500   ...(1)

(x+y)5=3000

x+y=3000/5=600   ...(2)

adding (1) and (2)

2x=1100

x=1100/2=550

550 +y=600

y=600-550=50

speed of plane in still air=550 m/hr

speed of wind=50 m/hr

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

i am unable to solve this problem

step-by-step explanation: