the perimeter of rectangle a is three times that of rectangle b. rectangle b
is 4 cm long and 6 cm wide. given that rectangle a and rectangle b are
similar, what is the perimeter of rectangle a?
a. 72 cm
b. 60 cm
c. 20 cm
d. 24 cm

Step-by-step explanation:

Rectangle B :

P = 2(L + W)

L = 4

W = 6

P = 2(4 + 6)P = 2(10)...P = 20 cm

so the perimeter of rectangle B is 20 cm

perimeter of rectangle A is 3 times bigger...

so perimeter of rectangle A is : (3 * 20) = 60 cm <==

another way to do this is if rectangle A is 3 times bigger, then the length and width are 3 times bigger too

so if rectangle B has a length of 4 cm, then rectangle A has a length of

(4 * 3) = 12 cm

and if rectangle B has a width of 6 cm, then rectangle A has a width of

(6 * 3) = 18 cm

so rectangle A perimeter is :

P = 2(L + W)

L = 12

W = 18

P = 2(12 + 18)...P = 2(30)P = 60 cm <===

either way u choose to do it will give u the same answer