Agambling book recommends the following "winning strategy"for the
game of roulette. it recommends that a gambler bet $1 onred. if red
appears (which has probablity 18/38), then the gamblershould take
her $1 profit and quit. if the gambler loses this bet(which has
probablity 20/38 of occurring), she should makeadditional $1 bets
on red on each of the next two spins of theroulette wheel and then
quite. let x denote the gambler's winningswhen she quites.

(a) find p{x > 0}.

(b) are you concinved that the strategy is indeed a
"winning"strategy? explain your answer.

(c) find e[x].

Please see attachment

Step-by-step explanation:

Please see attachment

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

$32,660

step-by-step explanation: