Apaintball is fired from a gun with a force of 59 n at an angle of elevation of 1°. if the force due to gravity on the
paintball is 0.0294 n, then answer the following:
a. is this angle of elevation enough to overcome the initial force due to gravity and still have an angle of elevation
greater than 0.5°?
b. what is the resultant magnitude of the vector in the direction of the paintball?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

25/6

step-by-step explanation:

you multiply 4 by the denominator (4*6=24) and add it to the numerator which makes it 25/6.

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x

look at the picture i have filled out a table for it. hope this .