It is 90 ft between the bases of baseball diamond. a catcher throws a baseball to the shortstop who is half-way between second and third bases.
how long is his throw?

127.3 ft

Step-by-step explanation:

A baseball diamond is constructed in a square shape.

The sides are 90 ft each

If a catcher throws a baseball to the shortstop who is half-way between second and third bases, the distance between the third base and the short stop = 1/2(90)

= 45 ft

length of the throw is found using Pythagoras theorem.

Hypothenus ^2 = opposite ^2 + adjacent ^2

= 90^2 + 45^2

Hypothenus = √8100 + 2025

=√10125

= 100.62 ft (approximately)

no

step-by-step explanation: