Steve thinks that he has a fair coin with equal probability of landing head or tails. he is ready to change his mind if in a long enough series of flips the coin will land on the same side. steve decided that "long enough" means the probability of a fair coin landing the same way is less than 1%. what is the shortest series that will allow steve to declare that the coin is not fair?

a. 7 flips

b. 8 flips

c. 99 flips

d. 101 flips

maybe c idk

A. 7 flips

Step-by-step explanation:

the shortest series that will allow Steve to declare that the coin is not fair = n

The probability of a coin tossed n times to land on the same side is given as;

Pn =1/2^n

For Pn < 1% = 0.01

1/2^n < 0.01

nLog(1/2) < Log (0.01)

n > Log(0.01)/Log(1/2)

n > 6.64

The shortest n = 7

Therefore, the shortest series that will allow Steve to declare that the coin is not fair

= 7 flips.

i dont know i just need points

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: