What is the equation of the line in the slope-interception form that passes through (3,-1) and (-1,5)

y+1=-3/2(x-3)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(5-(-1))/(-1-3)

m=(5+1)/-4

m=6/-4

simplify

m=-3/2

y-y1=m(x-x1)

y-(-1)=-3/2(x-3)

y+1=-3/2(x-3)

goog may have it for you

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204